Distributive law :A+BC = (A+B)(A+C)

Ajay Avale
Ajay Avale
Created on Sep 24, 2025 0 0 0
Distributive law :A+BC = (A+B)(A+C)
100%

Procedure

  1. Add IC 74LS32 into ICBase-1 (74LS32).
  2. Add IC 74LS08 into ICBase-2 (74LS08).
  3. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS32).
  4. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS08).
  5. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS08).
  6. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS32).
  7. Connect Input-14 to Pin-1 (Input) of ICBase-1 (74LS32).
  8. Connect Input-13 to Pin-1 (Input) of ICBase-2 (74LS08).
  9. Connect Input-12 to Pin-2 (Input) of ICBase-2 (74LS08).
  10. Connect Pin-2 (Input) of ICBase-1 (74LS32) to Pin-3 (Output) of ICBase-2 (74LS08).
  11. Connect Output-9 to Pin-3 (Output) of ICBase-1 (74LS32).
  12. Add IC 74LS32 into ICBase-3 (74LS32).
  13. Add IC 74LS08 into ICBase-4 (74LS08).
  14. Connect Input-4 to Pin-1 (Input) of ICBase-3 (74LS32).
  15. Connect Input-3 to Pin-2 (Input) of ICBase-3 (74LS32).
  16. Connect Pin-1 (Input) of ICBase-4 (74LS08) to Pin-3 (Output) of ICBase-3 (74LS32).
  17. Connect Input-4 to Pin-4 (Input) of ICBase-3 (74LS32).
  18. Connect Input-2 to Pin-5 (Input) of ICBase-3 (74LS32).
  19. Connect Pin-2 (Input) of ICBase-4 (74LS08) to Pin-6 (Output) of ICBase-3 (74LS32).
  20. Connect Output-4 to Pin-3 (Output) of ICBase-4 (74LS08).
  21. Connect VCC Port to Pin-20 (VCC) of ICBase-4 (74LS08).
  22. Connect GND Port to Pin-7 (Ground) of ICBase-4 (74LS08).
  23. Connect VCC Port to Pin-20 (VCC) of ICBase-3 (74LS32).