(AB)C = A(BC)

tanuja thorat
tanuja thorat
• Created on Sep 11, 2025 • 0 • 0 • 0
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(AB)C = A(BC)
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Procedure

  1. Add IC 74LS08 into ICBase-1 (74LS08).
  2. Add IC 74LS08 into ICBase-2 (74LS08).
  3. Connect Pin-1 (Input) of ICBase-1 (74LS08) to Input-15.
  4. Connect Pin-2 (Input) of ICBase-1 (74LS08) to Input-14.
  5. Connect Pin-1 (Input) of ICBase-2 (74LS08) to Input-13.
  6. Connect Pin-2 (Input) of ICBase-2 (74LS08) to Pin-3 (Output) of ICBase-1 (74LS08).
  7. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS08).
  8. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS08).
  9. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS08).
  10. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS08).
  11. Connect Output-0 to Pin-3 (Output) of ICBase-2 (74LS08).
  12. Add IC 74LS08 into ICBase-4 (74LS08).
  13. Add IC 74LS08 into ICBase-5 (74LS08).
  14. Connect Pin-1 (Input) of ICBase-4 (74LS08) to Input-2.
  15. Connect Pin-1 (Input) of ICBase-5 (74LS08) to Input-1.
  16. Connect Pin-2 (Input) of ICBase-5 (74LS08) to Input-0.
  17. Connect Pin-2 (Input) of ICBase-4 (74LS08) to Pin-3 (Output) of ICBase-5 (74LS08).
  18. Connect GND Port to Pin-7 (Ground) of ICBase-4 (74LS08).
  19. Connect GND Port to Pin-7 (Ground) of ICBase-5 (74LS08).
  20. Connect Output-1 to Pin-3 (Output) of ICBase-4 (74LS08).
  21. Connect VCC Port to Pin-20 (VCC) of ICBase-4 (74LS08).
  22. Connect VCC Port to Pin-20 (VCC) of ICBase-5 (74LS08).