(AB)C = A(BC)

Shivam Potpalliwar
Shivam Potpalliwar
• Created on Oct 13, 2025 • 0 • 0 • 0
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(AB)C = A(BC)
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Procedure

  1. Add IC 74LS08 into ICBase-1 (74LS08).
  2. Add IC 74LS08 into ICBase-2 (74LS08).
  3. Add IC 74LS08 into ICBase-3 (74LS08).
  4. Add IC 74LS08 into ICBase-4 (74LS08).
  5. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS08).
  6. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS08).
  7. Connect VCC Port to Pin-20 (VCC) of ICBase-3 (74LS08).
  8. Connect VCC Port to Pin-20 (VCC) of ICBase-4 (74LS08).
  9. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS08).
  10. Connect GND Port to Pin-7 (Ground) of ICBase-3 (74LS08).
  11. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS08).
  12. Connect GND Port to Pin-7 (Ground) of ICBase-4 (74LS08).
  13. Connect Pin-1 (Input) of ICBase-1 (74LS08) to Input-14.
  14. Connect Pin-2 (Input) of ICBase-1 (74LS08) to Input-13.
  15. Connect Pin-1 (Input) of ICBase-2 (74LS08) to Pin-3 (Output) of ICBase-1 (74LS08).
  16. Connect Pin-2 (Input) of ICBase-2 (74LS08) to Input-12.
  17. Connect Output-8 to Pin-3 (Output) of ICBase-2 (74LS08).
  18. Connect Pin-1 (Input) of ICBase-3 (74LS08) to Input-13.
  19. Connect Pin-2 (Input) of ICBase-3 (74LS08) to Input-12.
  20. Connect Pin-1 (Input) of ICBase-4 (74LS08) to Pin-3 (Output) of ICBase-3 (74LS08).
  21. Connect Pin-2 (Input) of ICBase-4 (74LS08) to Input-14.
  22. Connect Output-7 to Pin-3 (Output) of ICBase-4 (74LS08).