(AB)C=A(BC)

Raghav Deshpande
Raghav Deshpande
• Created on Sep 15, 2025 • 0 • 0 • 0
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(AB)C=A(BC)
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Procedure

  1. Add IC 74LS08 into ICBase-1 (74LS08).
  2. Add IC 74LS08 into ICBase-2 (74LS08).
  3. Add IC 74LS08 into ICBase-3 (74LS08).
  4. Add IC 74LS08 into ICBase-4 (74LS08).
  5. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS08).
  6. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS08).
  7. Connect GND Port to Pin-7 (Ground) of ICBase-3 (74LS08).
  8. Connect GND Port to Pin-7 (Ground) of ICBase-4 (74LS08).
  9. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS08).
  10. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS08).
  11. Connect VCC Port to Pin-20 (VCC) of ICBase-3 (74LS08).
  12. Connect VCC Port to Pin-20 (VCC) of ICBase-4 (74LS08).
  13. Connect Pin-1 (Input) of ICBase-1 (74LS08) to Input-15.
  14. Connect Pin-2 (Input) of ICBase-1 (74LS08) to Input-14.
  15. Connect Pin-1 (Input) of ICBase-2 (74LS08) to Pin-3 (Output) of ICBase-1 (74LS08).
  16. Connect Pin-2 (Input) of ICBase-2 (74LS08) to Input-13.
  17. Connect Output-15 to Pin-3 (Output) of ICBase-2 (74LS08).
  18. Connect Pin-1 (Input) of ICBase-3 (74LS08) to Input-15.
  19. Connect Pin-1 (Input) of ICBase-4 (74LS08) to Input-14.
  20. Connect Pin-2 (Input) of ICBase-4 (74LS08) to Input-13.
  21. Connect Pin-2 (Input) of ICBase-3 (74LS08) to Pin-3 (Output) of ICBase-4 (74LS08).
  22. Connect Output-14 to Pin-3 (Output) of ICBase-3 (74LS08).