A⋅(B+C)=A⋅B+A⋅C Distributive Law

Shreya
Shreya Narute
• Created on Jul 24, 2025 • 0 • 0 • 2
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A⋅(B+C)=A⋅B+A⋅C Distributive Law
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Integrated Circuits Used

74LS32 74LS08

Procedure

  1. Add IC 74LS32 into ICBase-1 (74LS32).
  2. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS32).
  3. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS32).
  4. Connect Input-15 to Pin-1 (Input) of ICBase-1 (74LS32).
  5. Connect Input-14 to Pin-2 (Input) of ICBase-1 (74LS32).
  6. Add IC 74LS08 into ICBase-2 (74LS08).
  7. Connect Pin-1 (Input) of ICBase-2 (74LS08) to Pin-3 (Output) of ICBase-1 (74LS32).
  8. Connect Input-12 to Pin-2 (Input) of ICBase-2 (74LS08).
  9. Connect Output-11 to Pin-3 (Output) of ICBase-2 (74LS08).
  10. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS08).
  11. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS08).
  12. Add IC 74LS08 into ICBase-3 (74LS08).
  13. Connect Input-10 to Pin-1 (Input) of ICBase-3 (74LS08).
  14. Connect Input-9 to Pin-2 (Input) of ICBase-3 (74LS08).
  15. Connect VCC Port to Pin-20 (VCC) of ICBase-3 (74LS08).
  16. Connect GND Port to Pin-7 (Ground) of ICBase-3 (74LS08).
  17. Connect Pin-2 (Input) of ICBase-4 (74LS32) to Pin-3 (Output) of ICBase-3 (74LS08).
  18. Add IC 74LS08 into ICBase-5 (74LS08).
  19. Connect VCC Port to Pin-20 (VCC) of ICBase-5 (74LS08).
  20. Connect GND Port to Pin-7 (Ground) of ICBase-5 (74LS08).
  21. Connect Input-0 to Pin-1 (Input) of ICBase-5 (74LS08).
  22. Connect Input-1 to Pin-2 (Input) of ICBase-5 (74LS08).
  23. Connect Pin-1 (Input) of ICBase-4 (74LS32) to Pin-3 (Output) of ICBase-5 (74LS08).
  24. Add IC 74LS32 into ICBase-4 (74LS32).
  25. Connect Output-4 to Pin-3 (Output) of ICBase-4 (74LS32).
  26. Connect GND Port to Pin-7 (Ground) of ICBase-4 (74LS32).
  27. Connect VCC Port to Pin-20 (VCC) of ICBase-4 (74LS32).