(A+B)' = A'B'

Gargi
Gargi Padate
Created on Jul 31, 2025 0 0 3
(A+B)' = A'B'
100%

Integrated Circuits Used

Procedure

  1. Connect Pin-1 (Input) of ICBase-1 (74LS32) to Input-14.
  2. Connect Pin-2 (Input) of ICBase-1 (74LS32) to Input-13.
  3. Connect Pin-3 (Output) of ICBase-1 (74LS32) to Output-14.
  4. Connect Pin-1 (Input) of ICBase-2 (74LS04) to Output-14.
  5. Connect Output-4 to Pin-2 (Output) of ICBase-2 (74LS04).
  6. Connect Pin-1 (Input) of ICBase-3 (74LS04) to Input-14.
  7. Connect Pin-3 (Input) of ICBase-3 (74LS04) to Input-13.
  8. Connect Pin-1 (Input) of ICBase-4 (74LS08) to Pin-2 (Output) of ICBase-3 (74LS04).
  9. Connect Pin-2 (Input) of ICBase-4 (74LS08) to Pin-4 (Output) of ICBase-3 (74LS04).
  10. Connect Output-3 to Pin-3 (Output) of ICBase-4 (74LS08).
  11. Add IC 74LS32 into ICBase-1 (74LS32).
  12. Add IC 74LS04 into ICBase-2 (74LS04).
  13. Add IC 74LS04 into ICBase-3 (74LS04).
  14. Add IC 74LS08 into ICBase-4 (74LS08).
  15. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS32).
  16. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS04).
  17. Connect GND Port to Pin-7 (Ground) of ICBase-3 (74LS04).
  18. Connect GND Port to Pin-7 (Ground) of ICBase-4 (74LS08).
  19. Connect VCC Port to Pin-20 (VCC) of ICBase-4 (74LS08).
  20. Connect VCC Port to Pin-20 (VCC) of ICBase-3 (74LS04).
  21. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS04).
  22. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS32).