8:1 using 4:1 reduction

Chaitanya
Chaitanya Kulkarni
Created on Aug 25, 2021 0 0 2
8:1 using 4:1 reduction
100%

Integrated Circuits Used

Description

f(a,b,c) = (sum)m(0,1,3,5,6)

Procedure

  1. Connect Pin-20 (VCC) of ICBase-3 (74LS153) to VCC Port.
  2. Connect Input-0 to Pin-2 (Input) of ICBase-3 (74LS153).
  3. Connect Input-1 to Pin-18 (Input) of ICBase-3 (74LS153).
  4. Connect Input-2 to Pin-18 (Input) of ICBase-3 (74LS153).
  5. Connect Pin-2 (Input) of ICBase-3 (74LS153) to Input-1.
  6. Connect Pin-1 (Input) of ICBase-2 (74LS04) to Input-0.
  7. Connect Pin-2 (Output) of ICBase-2 (74LS04) to Pin-6 (Input) of ICBase-3 (74LS153).
  8. Connect VCC Port to Pin-5 (Input) of ICBase-3 (74LS153).
  9. Connect Input-0 to Pin-4 (Input) of ICBase-3 (74LS153).
  10. Connect Pin-3 (Input) of ICBase-3 (74LS153) to Pin-2 (Output) of ICBase-2 (74LS04).
  11. Connect Input-2 to Pin-4 (Input) of ICBase-3 (74LS153).
  12. Connect Pin-1 (Input) of ICBase-2 (74LS04) to Input-2.
  13. Connect Input-0 to Pin-18 (Input) of ICBase-3 (74LS153).
  14. Add IC 74LS04 into ICBase-2 (74LS04).
  15. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS04).
  16. Connect Pin-8 (Ground) of ICBase-3 (74LS153) to GND Port.
  17. Connect Output-0 to Pin-7 (Output) of ICBase-3 (74LS153).
  18. Connect GND Port to Pin-1 (Input) of ICBase-3 (74LS153).
  19. Add IC 74LS153 into ICBase-3 (74LS153).
  20. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS04).