xor using basic gates.

vedha vamsi
vedha vamsi sai
Created on Jun 17, 2021 0 0 3
xor using basic gates.
100%

Integrated Circuits Used

Description

here we want three gates they are and,not,or gates.take first and gate in this first pin is A connected to input 15 and same A is connected to first pin in not gate.and output of 1st pin in not is connected to 4th pin of and gate.and B is taken at 5pin of and gate and it is connected to 14 pin of input .same b is connected to3rd pin of not gate .and the output of 3rd pin in not gate is connected to 2nd pin in and gate.now the output of 1,2nd pins in and gate is connected to 1st pin or gate.and 4,5 pins output is connected to 2nd pin of or gate .now the ouput of 1,2 pins in or gate is connected to 0 output.circuits shows low value when both input values are low or high.in other cases it shoes high value.

Procedure

  1. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS08).
  2. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS08).
  3. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS04).
  4. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS04).
  5. Connect GND Port to Pin-7 (Ground) of ICBase-3 (74LS32).
  6. Connect VCC Port to Pin-20 (VCC) of ICBase-3 (74LS32).
  7. Connect Input-15 to Pin-1 (Input) of ICBase-1 (74LS08).
  8. Connect Input-14 to Pin-5 (Input) of ICBase-1 (74LS08).
  9. Connect Pin-1 (Input) of ICBase-2 (74LS04) to Input-15.
  10. Connect Pin-4 (Input) of ICBase-1 (74LS08) to Pin-2 (Output) of ICBase-2 (74LS04).
  11. Connect Pin-3 (Input) of ICBase-2 (74LS04) to Input-14.
  12. Connect Pin-2 (Input) of ICBase-1 (74LS08) to Pin-4 (Output) of ICBase-2 (74LS04).
  13. Connect Pin-1 (Input) of ICBase-3 (74LS32) to Pin-3 (Output) of ICBase-1 (74LS08).
  14. Connect Pin-2 (Input) of ICBase-3 (74LS32) to Pin-6 (Output) of ICBase-1 (74LS08).
  15. Connect Output-0 to Pin-3 (Output) of ICBase-3 (74LS32).
  16. Add IC 74LS08 into ICBase-1 (74LS08).
  17. Add IC 74LS32 into ICBase-3 (74LS32).
  18. Add IC 74LS04 into ICBase-2 (74LS04).