F=(B'.D)+(A+(C.D'))' by 1911159

Meraj
Meraj Mohammed Bhuiyan
Created on Apr 27, 2021 0 0 3
F=(B'.D)+(A+(C.D'))' by 1911159
100%

Integrated Circuits Used

Procedure

  1. Add IC 74LS04 into ICBase-1 (74LS04).
  2. Add IC 74LS08 into ICBase-2 (74LS08).
  3. Add IC 74LS32 into ICBase-3 (74LS32).
  4. Connect VCC Port to Pin-20 (VCC) of ICBase-1 (74LS04).
  5. Connect VCC Port to Pin-20 (VCC) of ICBase-2 (74LS08).
  6. Connect VCC Port to Pin-20 (VCC) of ICBase-3 (74LS32).
  7. Connect GND Port to Pin-7 (Ground) of ICBase-1 (74LS04).
  8. Connect GND Port to Pin-7 (Ground) of ICBase-2 (74LS08).
  9. Connect GND Port to Pin-7 (Ground) of ICBase-3 (74LS32).
  10. Connect Pin-1 (Input) of ICBase-1 (74LS04) to Input-14.
  11. Connect Pin-1 (Input) of ICBase-2 (74LS08) to Pin-2 (Output) of ICBase-1 (74LS04).
  12. Connect Pin-2 (Input) of ICBase-2 (74LS08) to Input-12.
  13. Connect Pin-1 (Input) of ICBase-3 (74LS32) to Pin-3 (Output) of ICBase-2 (74LS08).
  14. Connect Pin-4 (Input) of ICBase-2 (74LS08) to Input-13.
  15. Connect Pin-3 (Input) of ICBase-1 (74LS04) to Input-12.
  16. Connect Pin-5 (Input) of ICBase-2 (74LS08) to Pin-4 (Output) of ICBase-1 (74LS04).
  17. Connect Pin-4 (Input) of ICBase-3 (74LS32) to Pin-6 (Output) of ICBase-2 (74LS08).
  18. Connect Pin-5 (Input) of ICBase-3 (74LS32) to Input-15.
  19. Connect Pin-5 (Input) of ICBase-1 (74LS04) to Pin-6 (Output) of ICBase-3 (74LS32).
  20. Connect Pin-2 (Input) of ICBase-3 (74LS32) to Pin-6 (Output) of ICBase-1 (74LS04).
  21. Connect Output-0 to Pin-3 (Output) of ICBase-3 (74LS32).